A bag of potato chips is packaged at sea level (1.00 atm) and has a volume of 315mL. If this bag of chips is transported to Denver (0.775 atm), what will the new volume of the bag be?
(Assume the temp is constant)
this is using combined gas law...
help please??
2007-05-15 16:43:51 · 5 answers · asked by Mandi M 1 in Science & Mathematics ➔ Chemistry
At constant temperature we use the Boyle's law
p1V1 = p2 V2
Substitute these values :
1.00 x 315 = 0.775 V2
V2 = 406 mL
2007-05-15 16:50:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Since the chips themselves dont change volume, it should be stipulated that the volume of GAS in the bag is 315 mL. By the ideal gas law, P1V1=P2V2. So the new volume V2 would be
......315/0.775
2007-05-15 16:50:17 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
315(1.00/0.775) =406.45ml
2007-05-15 16:53:38 · answer #3 · answered by jsardi56 7 · 0⤊ 0⤋
p1v1=p2v2
1 atm X .315L/ .775 atm =X
2007-05-15 16:51:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1*.315L = .315
.775*V = .315
V=.40645L=406.45mL
2007-05-15 16:47:52 · answer #5 · answered by xmodry 2 · 0⤊ 0⤋