divide x*x-2x-35?

Answer 1

I am guessing that by x*x you meant x^2 or x squared.

If so, it is x^2 - 2x - 35 factoring...
(x-7) (x+5)

Answer 2

Maybe you want to factor it out: x^2 - 2x - 35
Factoring takes the general form (x + a)(x + b). There can be coefficients (a constant number that multiplies something) by the x. For example, it could be (7x + a)(2x + b), etc.
Now, when you factor, you need to find a and b. Given your quadratic equation, x^2 - 2x - 35, a and b must add up to -2 and they must have a product of -35. So, what numbers when multiplied give 35? Basically, 1/35 and 7/5. Next, which pair has a difference of 2? 7 and 5 do. Okay, now we have to consider the negative sign on the 35. That means one of the numbers (5 or 7) has to be negative. Well, since they add up to -2, 7 must be negative, because 5-7 = -2
So, it's factored like this: (x - 7)(x + 5)
Sometimes you want to find the solutions to a quadratic (graphically speaking, that where the graph crosses the x-axis). To solve, set the expression equal to 0:
(x - 7)(x + 5) = 0
This equals 0 when x = 7 or when x = -5.
I hope that helped!

Answer 3

I think you mean factor not divide.
x*x-2x-35
(x-7)(x+5)

Answer 4

do you mean factor this trinomial?
x^2-2x-35,
(x-7)(x+5)

Answer 5

x*x-2x-35=0
x^2-2x-35=0
x^2-7x+5x-35=0
(x-7)(x+5)=0
x=7, x=-5

Answer 6

This is a quadratic equation. i.e. ax^2+bx+c = 0
Hence applying the rule.
(x-7)(x+5) = 0
i.e. x=7 & x=-5

Regards,
Amit

Answer 7

by what or in to what? i can help if the problem is all here

Answer 8

ugh...ugh....noooo!! my brain is having a nervous breakdown!!! O.O

Answer 9

i think you have to use long division
the algebraic version

Answer 10

by what