1. Simplify and evaluate:
(x7y-4z0/5-2x3y-8z-9)2
4. Perform the indicated operations:
(x2 – 4x + 1) – (-8x2 + 2x – 6) – (x2 + 3x – 5
6. Multiply:
(x4 + 3x2 – 1)(x2 – x + 2)
2007-05-15
12:01:46
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8 answers
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asked by
Eclipse
5
in
Science & Mathematics
➔ Mathematics
the first one is powers
2007-05-15
12:05:21 ·
update #1
i am asking for help with these problems.. so that i can figure out how to do the rest if i see the work and not in the book i can figure it out
2007-05-15
12:22:01 ·
update #2
First, clean them up.
(is that a zero?)
4z0/5 = 4z(0) = 0
1) (2)x7y - (2)4z0/5 -(2)2x3y - (2)8z - (2)9 =
14xy - 0 - 12xy - 16z - 18 =
2xy - 16z - 18
4) first simplify, get rid of the parens:
(x2 -4x + 1) - (-8x2 + 2x - 6) - (x2 + 3x - 5)
x2 - 4x + 1 + 16x - 2x + 6 - 2x - 3x - 5
combine like terms
(2x - 4x + 16x - 2x - 2x - 3x) + (1 + 6 - 5)
18x - 11x + 2
7x + 2
6) Again, combine like terms first:
(4x + 6x - 1) (2x - x + 2)
(10x - 1) (x + 2)
10x^2 - x + 20x - 2
10x^2 - 19x - 2
2007-05-15 12:27:20
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answer #1
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answered by Mark B 2
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i can't read the first one so here is number 4
you have to combine the like terms, circle all with x2, now x2 is really 1x2 so you have: 1(x2) - -8(x2) -1(X2) = 8x2, now put a triangle around all the x terms, -4(X) - 2(X) - 3(X) = -9x, now a square around all numbers without an x, 1 - -6 - -5 = 12
so the answer is 8x2 - 9x + 12
2007-05-15 19:14:52
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answer #2
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answered by ali 1
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Math - you say no one helped you the first time -
Does this include your school Teacher, who quite possibly,
You never asked for help?
2007-05-15 19:09:49
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answer #3
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answered by Living In Korea 7
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1) 2x*14y-8z divided by 10-4x*16y-16z-18
________
10-4x*16y-16z-18 -8z divided by -16z = 1/2 z
14y/16y=7/8y
2x/-4x= -0.5x
10-18= -8
the answer is -1/2x* 7/8y- 1/2z-8
2007-05-15 19:13:33
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answer #4
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answered by marty 2
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LOL, You want us to do your homework? Pay attention in class or read the book.
2007-05-15 19:09:39
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answer #5
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answered by zbalat 7
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yeah. looks like fun. try asking ur professor.
2007-05-15 19:09:05
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answer #6
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answered by <3.love.tennis. 4
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i know the answer and you dont thats pretty funny!!LOL!!!!
2007-05-15 19:05:54
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answer #7
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answered by Anonymous
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cant help .... lolz!!
2007-05-15 19:05:33
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answer #8
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answered by Rose 3
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