Chemistry Mols problem help!!!!?

Question

24.55 grams of a metal whose temperature is 102.0 °C i dropped into 75.2 grams of distilled water at a temperaure of 21.0 °C. The temperature of the water rises to 22.2 °C. The specific heat of water is 1 cal/grams · °C. What is the specific heat of the metel?

Answer 1

energy lost by metal = energy gained by water

q = (mass) (delta t) (specific heat)

(24.55 g) (102 - 22.2 C) (x) = (75.2 g) (22.2 - 21 C) (1.00 cal/g-C)

Answer 2

24.55*s*(102-22.2) = 75.2*1*(22.2-21)

or s = 0.046 cal/g