The height from which you are released is 62.5 meters. However, the last 20.8 meters are used to slow you down from your maximum speed to rest (it's a good thing). Based on these two heights, what would be the following, taking the ground to be the origin, and up to be the positive direction:
(i) The change in position from the release point to the point at which the braking mechanism engages is -41.7 meters up.
How do you calculate the time you are in free fall (the time it takes you to travel from the release point to the point at which the braking mechanism engages?
2007-05-15 08:08:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
v = at
s = (at^2)/2 where a = g nominally, 9.81 m/sec^2 or 32.18 ft/sec^2.
The proper motion of an object in free fall is symmetric, up or down.
2007-05-15 08:19:13 · answer #1 · answered by Uncle Al 5 · 0⤊ 0⤋
Giant Drop Physics
2016-11-04 04:57:47 · answer #2 · answered by ? 4 · 0⤊ 0⤋
The gravity acceleration is the real problem . The first second of free fall is 33 ft and the second velocity acceleration is 66 ft. See if that helps.
2007-05-15 08:33:20 · answer #3 · answered by JOHNNIE B 7 · 0⤊ 0⤋
velocity = gravity x time 9.8 is the force of gravity pulling down on upton 2.6 seconds is the time it took for him to fall v= 9.8 x 2.6 v= 25.48 distance = 1/2 gravity time^2 1/2 x 9.8 x 2.6^2 distance = 33.124 meters
2016-03-18 23:58:00 · answer #4 · answered by Anonymous · 0⤊ 0⤋