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I don't know ho to type in this math problem, so I take a pictures

http://img174.imageshack.us/my.php?image=math001qh8.jpg

It's (x^3)(y^4)/(x^2)(y), sorry for the poor pictures quality

Can some one help me out? Thanks

2007-05-15 07:16:01 · 3 answers · asked by Anonymous in Education & Reference Homework Help

I'm talking about number 14b).

2007-05-15 07:17:10 · update #1

Thanks for the help, but what happen when you have different root? Like

fifth root of (a^4)/third root of (a^2)

2007-05-15 08:05:36 · update #2

3 answers

Since both are the fifth root you can combine the fraction's parts into one big fraction, then use rules of division and subtract the corresponding exponents. This leaves

fifth root [x^(3-2) y^(4-1)]

= fifth root (xy^3)

2007-05-15 07:24:02 · answer #1 · answered by hayharbr 7 · 2 0

5th root x^3y^4/ x^2y

5th root x^3-x^2=x
y^4-y=y^3

5th root xy^3

2007-05-15 08:56:13 · answer #2 · answered by Dave aka Spider Monkey 7 · 0 0

First group like terms: 14xy - 7xy - 6xy Because the 7xy and the 6xy are both negative, you would subtract 13xy from 14xy, leaving you with 1xy, or just xy. -6x + 8x Because 6x is negative, you would subtract it from 8x and end up with 2x. Your final answer would be: xy + 2x

2016-05-18 22:35:03 · answer #3 · answered by maxine 4 · 0 0

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