what is 152.5deg K converted into deg. C.?

Question

If the volume of a gas container at 32.0deg. C changes from 1.55 L to 755mL, what will hte final temp be?

I came up with...1.55/305=0.775/T = 152.5K which is equal to 425.5C. I sure I am wrong but can anyone help?

Answer 1

0°C = 273.15 K

So, 152.5 K = -120.65°C

Answer 2

C = K - 273

= 152.5 - 273 = -120.5

for the other question, use this formula:

T1/V1 = T2/V2

solve for T2

T2 = T1V2/V1

for gas law calculations, temperatures must be in K. so you'll need to convert the given 32 deg C in to kelvin:

K = C + 273 = 32 + 273 = 305

you'll also need to get the given volumes into the same units. so you could convert the 1.55 L into mL:

1.55 L x [1000 mL / 1L] = 1550 mL

now you can plug your values into the equation:

T2 = T1V2/V1 = (305)(755)/1550 = 148.6 K

if you want that in celsius:

C = K - 273 = 148.6 - 273 = -124.4

Answer 3

If pressure is constant

we can use Charles' law

V1 / T1 = V2 / T2

32 °C = 273 + 32 = 305 K

1.55 / 305 = 0.775 / T2

0.00508 = 0.775 / T2

T2 = 152.5 K

152.5 K - 273 = - 120.5°C

Answer 4

0 degree C is approx. 273 K So, 75 degree C = 273 + 75 = 348 K

Answer 5

No, son, you're supposed to subtract 273 to get from K to C.

K= C +273
C= K-273

Answer 6

152.5deg K -273 = -120.5 deg C

Answer 7

152.5 kelvin = -120.65 degrees Celsius

Answer 8

K = 273.15 + C