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1 mole of H2SO4 has 2 moles of Hydrogen atoms, 1 mole of Oxigen atoms and 4 moles os Sulfur atoms

1 : 2 = 0.25 : x

x = 0.50 moles

1 mole contains 6.02 x 10^23 atoms ( Avogadro's number)

1 : 6.02 x10^23 = 0.5 : x

x = 3.01 x 10^23 Hydrogen atoms

2007-05-15 03:55:04 · answer #1 · answered by Anonymous · 0 1

Since H2SO4 has two H+ per molecule, the formula to get the number of H+ atoms in 0.25 moles is 2x 0.25 x 6.022x 10^23 which is 3.011x 10^23

2007-05-15 04:06:47 · answer #2 · answered by lahomaokie 2 · 0 0

H2SO4 each molecule contains 2 atoms of Hydrogen

1mole of H2SO4 = 6.02 10^23 molecules H2SO4
0.25mole =0.25*6.0210^23moleculesH2SO4

and you multiply by 2

S 2* 0.25*6.0210^23= 3.01*10^23 atoms hydrogen

2007-05-15 04:04:29 · answer #3 · answered by maussy 7 · 0 0

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2016-05-17 12:48:34 · answer #4 · answered by Anonymous · 0 0

one million. on condition that in one million mole there is 6.02*10^23 molecules of H2SO4, then there could be 2 * 6.02*10^23 molecules of hydrogen, on condition that there are 2 atoms in line with molecule. likewise, there could be 6.02*10^23 atoms of sulfur and four * 6.02*10^23 molecules of oxygen. 2. it is purely approximately comparable to question one million. besides the incontrovertible fact that, there is in basic terms 2 H+(hydrogen ions) and one million SO4 2+ (sulfate ions). for this reason, be conscious an identical concept. there could be 2* (6.02*10^23 * 2.sixty 5) hydrogen ions (bear in concepts that 6.02*10^23 * 2.sixty 5 is the form of molecules of H2SO4) and purely 6.02*10^23 * 2.sixty 5 sulfate ions.

2016-12-11 10:05:43 · answer #5 · answered by Anonymous · 0 0

maurizia g's answer gets you halfway to the answer. There are 0.5 moles of hydrogen, but the question asked for the number of atoms. To find the number of atoms, multiply the number of moles times Avogadro's number:
0.5 * 6.0221415*10^23 = 3.01107075*10^23 atoms

sorry maurizia g... the rest of your answer wasn't there when I made my initial post

2007-05-15 04:01:54 · answer #6 · answered by Chad H 3 · 1 0

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