use pythagoras theorm: a^2 + b^2 = c^2 where c is the hypotenuse
in your case a & b will be north & east ( or vice versa) & c will be north-east
35^2 + 65^2 = c^2
1225 + 4225 = c^2
5450= c^2
sq.root 5450= c
c= 73.8km (1dp) although check this answer on calculator please cos I don't have one here & used my mobile phone!
2007-05-15 00:46:13
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answer #1
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answered by Just me 5
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Use Pythogaras' Theorem:
Let a represent the distance travelled north.
Let b represent the distance travelled east.
Let c represent the distance from the starting point.
Pythogaras' Theorem states that for a right-angled triangle:
c^2 = a^2 + b^2
So work out c^2, take the positive square root, and that's the final answer.
Note: This problem can be solved using Pythogaras' Theorem as when you travel north and east, you are actually making a right anlge. Join the final point and starting point with a line a you will have a right-angle triangle
2007-05-15 07:48:16
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answer #2
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answered by limck_dcp_cls 2
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Use the pythagorean theorem
a^2 + b^2 = c^2
35^2 + 65^2 = c^2
1225 + 4225 = c^2
5450 = c^2
Take the sqrt of both sides
c = +/- sqrt 5450
c = +/-73.8241153
c = 73.8 kilometers
2007-05-15 08:07:59
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answer #3
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answered by detektibgapo 5
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Hmm its sqrt(35^2 + 65^2) . Its the resultant vector.
= 73.82 approx = 70 km
2007-05-15 07:42:17
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answer #4
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answered by the_warper 2
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35^2 + 65^2 = x^2
1225 + 4225 = x^2
5450 = x^2
x= 73.8
2007-05-15 07:43:03
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answer #5
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answered by stacey_b 2
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c² = a² + b²
âc² = â(35)² + (65)²
âc² = â1225 + 4225
âc² = â5450
c = 73.8241153 km
c = 73.8 km rounded to one decimal place
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2007-05-15 09:21:32
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answer #6
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answered by SAMUEL D 7
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d = sqrt (35^2 + 65^2)
d = sqrt(5450)
d = 73.8 km
2007-05-15 07:43:36
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answer #7
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answered by michael_scoffield 3
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=Sqrt(35^2+65^2)
2007-05-15 07:44:25
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answer #8
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answered by rabi k 2
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Use the Pythagorean relation.
2007-05-15 08:02:10
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answer #9
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answered by Mark 6
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73.8km?
2007-05-15 07:41:59
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answer #10
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answered by elsewhere_for_eight_minutes 3
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