I need help with this challenging math problem quick! Can someone please help?

Question

1.) Solve using the addition method:
X – y = 12
2x + y = 3


2.) Solve:
Y = 3x
Y = 3x + 1

I appreciate everyones unique answer...I really needed help with this.

Answer 1

X – y = 12
2x + y = 3
3x = 15
x = 5
If x = 5, 5 -y=12
-7 = y
___________

Y = 3x
Y = 3x + 1

0 is NOT equal to 1

Whoever says there's an answer is either a genius or an idiot!

Answer 2

for question 1.....

simply add the equations....

x+2x + y -y = 12+3....
3x=15.....
>>>>>>>>>>>> x=5 <<<<<<<<<<<<

nw substitute value of x in any of the two equations....

5 -y =12
-y= 12 -5
-y=7
>>>>>>>>>> y= -7 <<<<<<<<<<<

For Question 2.....

There is no solution since the two line have same slope i.e. they are parallel.........
hence they will never intersect hence no value of x and y will satisfy both the equations

Answer 3

Hey look,
1) x -y =12
2x+y=3

ys will becrossed out
3x=15
x=3
3-y=12
y= -9

2)this means that
y-3x=0 ( times 3)
y-3x=1 (times -3)
3y-9x=0
-3y+9x=-3
xs will be crossed out
ys will be crossed out
therefore x=0 ,y=0

Answer 4

1. X – y = 12 ------- (1)
2x + y = 3 -------- (2)

(1) + (2)
(x-y) + (2x + y) = 12 +3
x - y + 2x + y = 15 cancel y
3x = 15
x = 5
y = x - 12
= 5 - 12
= -7

2. y = 3x
y = 3x + 1
I think it's not possible to solve this question.

Answer 5

In number 2, you have parallel lines. Note the slope which is the coefficient of x . That's 3 in both equations. Parallel lines don't intersect. So there's no solution. You might say the solution is the empty set.

Answer 6

1)
Do you know what "additon method" means, if not look it up:
In this case it is:
x - y = 12
2x+y = 3
----------------- +
3x + 0y = 15, so x=5 and y=-7

2) if you try the same here you get:
y = 3x + 1
y = 3x
------------- -
0y = 0x + 1 so 0=1 ???????????????
Clearly this set of equations has no solution!!

Answer 7

1)add the both equations .y cancels out and you get
3x=15
x=5
and y= -7


2)this equation has no solution