2007-05-14 19:54:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the diagnol of the sq will be equal to the diameter of the circle.
hence side*2^0.5 = 2 * 10.
squaring both sides => (side^2) * 2 = 400
or (side^2) = 200
i.e area = 200 cm^2
2007-05-14 20:01:05 · answer #1 · answered by the_warper 2 · 0⤊ 1⤋
As someone mentioned, the diameter of the square is the diameter of the circle. And r^2 + r^2 = s^2 where r is the radius and s is the side of the square. The area of a square is s^2 which equals r^2 + r^2 = 10^2 + 10^2 = 200
or you can say s^2 + s^2 = (2r)^2 and solve for s^2, as a different answerer suggested.
2007-05-15 03:08:39 · answer #2 · answered by slik 2 · 0⤊ 0⤋
The diameter of the circle is 20 cm (twice the radius).
Now this diameter is also the diagonal of the square, so the sides of the square is x.
Then, 2x^2 = 20 by Phytogaras theorem.
x^2 = 10 = area of the square.
2007-05-15 02:58:57 · answer #3 · answered by looikk 4 · 0⤊ 1⤋
The thinking of the first answer is right but the math is wrong.
x^2 + x^2 = 20^2 is Pythagoras Theorem
2 x^2 = 400
x^2 = 200
x = 14.42
Area of square x*x which goes back to 200.
2007-05-15 03:06:25 · answer #4 · answered by Mike1942f 7 · 0⤊ 0⤋
Draw a diagram, you'll see the diagonal of the square is a diameter of the circle.
Let the side of the square be x,
By pythagorean theorem,
diagonal=diameter=root(x^2+x^2)
2*10cm =(root2)x
x=10(root2)cm.
Area of the square=x^2=[10(root2)]^2
=200cm^2
2007-05-15 03:04:31 · answer #5 · answered by shreya g 2 · 0⤊ 0⤋