The height of a triangle is 3 cm less than the base. The area of the triangle is 35cm squared.?

Question

Find the height and the length of the base. (h=b-3)

Answer 1

Area of triangle = 0.5 x base x height
So, b(b-3)(0.5) = 35
b^2 -3b -70 = 0
(b-10)(b+7)=0
b = 10, as base cannot be negative
So height is 7 cm, base is 10 cm

Answer 2

Let b = base
h = b - 3
(1/2).b.(b - 3) = 35
b² - 3b - 70 = 0
(b - 10).(b + 7) = 0
b = 10 (accepting + ve value)
Base = 10 cm
Height = 7 cm

Answer 3

(35^2)cm

A of Triangle: (Basic)
A = bh/2
35 = b(b-3)/2
35 =b^2-3b/2
70 = b^2 - 3b
b^2-3b-70 =0
(b - 10)(b+7) = 0
b-10 = 0 or b+7=0
b = 10 or b = -7
(-)ve values are rejected.
Hence, b = 10
if b = 10, h = 10-3
= 7
base = 10cm and height = 7cm

Answer 4

the backside of a triangle is 4 cm extra advantageous than the top: base = 4 + top the section is sixteen cm squared: 0.5 x base x top = sixteen locate the top AND THE length OF the backside: 0.5 x ( 4 + top ) x top = sixteen 0.5xh^2 + 2h -sixteen = 0 h^2 +4h -32 = 0 (h -4)(h+8)=0 top must be beneficial so top =4cm and base = 4 + top = 8cm

Answer 5

lame question

h = b - 3 is correct.

area = b xh /2

area = (b - 3) b / 2

area = b^2 - 3b / 2

quadratic equation! b^2 - 3b = area x2

b^2 - 3b - area x 2

solve for B using quadratic equation. take positive value of B as answer!