I have a few sq. root problems I need help with? 2-sq of x= -8, sq of w-1= -5 also- sq of 5+2x=7 help?

Answer 1

a) 2-√x=-8
>√x= 10
>x=100
b) √w-1=-5
>√w=-6
>w=36
c)√5+2x= 7
>5+2x=49
>2x=44
>x=22

Answer 2

flow the sqrt(2x+50) to the different area with the aid of subtracting it 2 sqrt (x+6) = 5 - sqrt(2x+50) sq. the two sides (the splendid area is FOIL) 4 (x+6) = (5 - sqrt(2x+50))(5 - sqrt(2x+50)) 4x + 24 = 25 - 10 sqrt (2x+50) + 2x + 50 flow the ten sqrt (2x+50) to the left and the 4x + 24 to the splendid with the aid of including the different 10 sqrt (2x+50) = -2x + fifty one sq. the two sides back a hundred (2x+50) = (-2x + fifty one)(-2x + fifty one) do this out, make it equivalent to 0, and resolve with the aid of quadratic formulation or if a possibility FOIL you ought to do it this manner simply by fact which you won't be in a position to sq. the two sides if issues are extra. it is you won't be in a position to easily sq. each ingredient in the unique subject and get 2x+50 + 4(x+6) = 25

Answer 3

Since you didn't put any parenthesis into your equations, there are several different interpretations.

2 - √x = -8
10 = √x
100 = x

√w - 1 = -5
√w = -4
The square root of any negative number is an imaginary number (i).
w = 16i


√5 + 2x = 7
2x = 7 - √5
x = (7 - √5)/2
.

Answer 4

2 - √x = - 8
- √x = - 6
√x = 6
x = 36

√(w - 1) = - 5
w - 1 = 25
w = 26

- √(5 + 2x) = 7
5 + 2x = 49
2x = 44
x = 22

or
- √5 + 2x = 7
√5 = 2x - 7
5 = 4x^2 - 28x + 49
4x^2 - 28x + 44 = 0
x^2 - 7x + 11 = 0
x^2 - 7x + (7/2)^2 = (7/2)^2 - 11
(x - 7/2) = ±√(5/4)
x = 7/2 - (1/2)√5,7/2 + (1/2)√5