algebra I math help?

Question

factoring using: x^2+bx+c
s^2(s to the 2nd power)

question: s^2-16s=+63

if you are willing to help in more problems email me please im soooooooooooo stuck

Answer 1

(s - 9)(s - 7)

Answer 2

s^2 - 16s -63 = 0
For these, I like to do a complete the square solution. Then s^2 -16 x + 64 -127 =0
(s-8)^2 = 127 and s = 8+/- sqrt(127).

Answer 3

s^2-16s=63

s^2-16s+__=63+__

s^2-16s+64=63+64 or 127

(s-8)^2=127

s-8= +or - square root of 127 or about +or - 11.27

add 8 to both sides and the value of s will be -19.27 or 3.27

im an indian too

Answer 4

s^2 - 16s = 63
s^2 - 16s - 63 = 0
( s - 8 - square root of ( 127 )).(s - 8 + square root of ( 127 )) = 0

Answer 5

(s-8)^2=127

Answer 6

s^2-16s=+63
s^2-16s-63=0
s^2-7s-9s-63=0
s(s-7)-9(s-7)=0
(s-7)(s-9)

Answer 7

i really dont no but im indian 2

Answer 8

s^2-16s-63=0
s=(16±√(16^2+4*63))/2
s=(16±√(256+252))/2
s=(16±√508)/2
s=8±√127
s=19.27
s=-3.27