Hard math problem?

Question

I Can't find the integral of -5x^-2 + x^-1. Somebody help pls?

Answer 1

Use the rule that the integral of x^n is x^(n+1) / (n+1) for the first part. For the second part, note that the derivative of ln(x) is 1/x, or x^-1, so the integral of x^-1 is ln(x). So you get:

-5 * x ^-1 / (-1) + ln(x) + C
= 5/x + ln(x) + C

Answer 2

is that the kind with the long S kind of thing in the beginning? isn't it supposed to be
S -5x^-2 + x^-1 dx ?
sorry i just got done w/ this chapter.
O WAIT I KNO!!
-5x^-2 = u
x^-1 = u'

so it would be like y' = (-5x^(-2)) + ((x^(-1))/ -5)

waaiit a minute,
k try finding the antiderivative 1st i got
y=(5x^(-1))+ x^0
but u can't rly have x^ 0 so mayb i was rite the 1st time.
i'm sorry i probably confused u more.

Answer 3

integral of -5^-2 is

(-5x^-1)/-1 which = 5/x

then, rewrite x^-1 as (1/x)

the integral of (1/x) = ln x

therefore, the answer is (5/x) + ln x

Answer 4

First write it in the form
-5/x^2+1/x

the answer is

(5 /x ) + lnx +c


hint:
(1/x)'=-1/x^2

(lnx)'=1/x

Answer 5

-5/2x^-1 - x, umm haven't done this for a while is it ok? i think the x^-1 is wrong, i used to know, i would have to go home and dig up the maths

Answer 6

six. random guess. thats a crazy problem good luck =] cuz idk how to do it