English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I am going through some of my recent homework assignments and I couldn't figure out the answer for this integration by parts problem.

Integral: x(e^3x)

Any help would be great!

2007-05-14 16:39:22 · 3 answers · asked by Mark S 1 in Science & Mathematics Mathematics

3 answers

u = x
du = dx

dv = e^3x
v = integral e^3x
v = (e^3x)/3

then rewrite, uv- integral vdu
so, (xe^3x)/3 - integral (e^3x)/3dx
therefore (1/9)(xe^3x) - ((e^3x)/3)

hope this helps

just remember uv - integral vdu

and always make you u such that du is simpler than u

2007-05-14 17:59:38 · answer #1 · answered by eldiko5@sbcglobal.net 2 · 0 0

Generally you want to choose for u the function that gets easier when you differentiate it. This is known as the ILATE rule. (see http://en.wikipedia.org/wiki/Integration_by_parts#The_ILATE_rule)
Here, e^3x never gets any easier, but the derivative of x is 1. Sodv is e^3x, v is (1/3) e^3x, and uv - vdu becomes
(1/3) x e^3x - integral (1/3) e^3x dx
This one is not so bad, sometimes you have to apply integeration by parts several times. In cases like that, tabular integraion aka the tic tac toe method comes in handy. Check the link I"ve given above, you'll see info on that as well.

2007-05-14 16:47:25 · answer #2 · answered by Joni DaNerd 6 · 1 1

let u = x
let dv = e^(3x)dx

good luck

2007-05-14 16:42:19 · answer #3 · answered by Demiurge42 7 · 2 0

fedest.com, questions and answers