2007-05-14 16:30:18 · 5 answers · asked by Lizzie 5 in Science & Mathematics ➔ Mathematics
sqrt(80n^10)
=sqrt(5*16*(n^5)^2)
=sqrt(5*4*4*(n^5)^2)
=4*sqrt(5)*n^5
2007-05-14 16:34:14 · answer #1 · answered by gudspeling 7 · 0⤊ 1⤋
80n^10 = 16 * 5 (n^5)^2
so you can simplyfy it as 4 n^5 â5
2007-05-14 23:36:09 · answer #2 · answered by Curious kid 2 · 0⤊ 1⤋
assuming that all of that is under the square root. you can simplify them separately since they are multiplied together. so the square root of n^10 is n^5 and the square root of 80 can be broken up into 16*5 so the answer is (4*n^5)*sqrt(5)
2007-05-14 23:36:48 · answer #3 · answered by Anonymous · 0⤊ 1⤋
sqrt(80n^10) =
sqrt(16*5*n^5*n^5) =
n>= 0
4n^5(sqrt(5))
n< 0
-4n^5(sqrt(5))
2007-05-14 23:35:24 · answer #4 · answered by Poetland 6 · 0⤊ 1⤋
4n^5*â5 for n greater than or equal to zero
-4n^5*â5 for n less than zero
2007-05-14 23:34:37 · answer #5 · answered by Demiurge42 7 · 0⤊ 1⤋