A plane flew 1750 km in 6 hours with a tail wind of constant velocity. It then flew back 540 kn in 3 hours with a head wind of the same velocity. Find the speed of the plane and the speed of the wind. I'm not sure on how to get the speed of the wind on this one...
2007-05-14 16:17:57 · 2 answers · asked by Lenola 1 in Science & Mathematics ➔ Mathematics
Downwind
Speed of plane = x kph
Speed of wind = y kph
Resultant speed = x + y kph
Distance = 1750 km
t1 = 1750 / (x + y) h
6x + 6y = 1750
3x + 3y = 875
Against wind
Speed of plane = x kph
Speed of wind = y kph
Resultant speed = x - y kph
Distance = 540 km
t2 = 3 h
3 = 540 / (x - y)
3x - 3y = 540
3x + 3y = 875
6x = 1415
x = 235.8 kph
3y = 875 - 707.5
y = 55.8 kph
2007-05-14 21:36:37 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Equations: 1750/(w+p) = 6; 540/(w-p) = 3. The algebra is trivial.
2007-05-14 23:21:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋