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2007-05-14 16:04:17 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

The greatest common factor of 192 and 588 is 12:

192r^2-588
12 * (16r^2 - 49)

However, both terms (16r^2 and 49) are perfect squares, and the factoring of the difference of two squares (x^2 - y^2) is (x - y)(x + y).

So this further factors to:

12 * (sqrt(16r^2) + sqrt(49))(sqrt(16r^2) - sqrt(49))
12 * (4r + 7) (4r - 7)

2007-05-14 16:07:52 · answer #1 · answered by McFate 7 · 1 0

GCD of 192 and 588 is 12

so 192r^2-588 = 12(16r^2-49)

now 16r^2-49 = (4r)^2-7^2 = (4r+7)(4r-7) using a^2-b^2 = (a+b)(a-b)

we get
12(4r+7)(4r-7)

2007-05-14 23:26:18 · answer #2 · answered by Mein Hoon Na 7 · 0 0

(r√192 - √588)(r√192 + √588)

2007-05-14 23:10:18 · answer #3 · answered by Demiurge42 7 · 0 0

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