Can you help me write this expanded logarithm into a single logarithm (all rules are reversible)?

Question

Expanded log:
-5log_b (x^2+4) + 6log_b (x) - log_b (b)
I know that log_b (b) is just = 1, or in this case, -1

log_b(x^2+4)^-5 + log_b (x)^6 - 1

( x^6 )
logb ---------------
[ (x^2+4)-^5 - 1 ]

Is this right or did I messed up a negative / rules of logarithm expansionism / misplacement numbers? Help...thanks :D

answers yahoo messed up my answer

( x^6 )
logb ---------------
[ (x^2+4)-^5 - 1 ]

answers yahoo messed my answer...TWICE!

( x^6 )
logb ( x^6 / [ (x^2+4)-^5 - 1 ] )

Answer 1

-5log_b (x^2+4) + 6log_b (x) - log_b (b)
= log_b (x^2+4)^(-5) + log_b (x)^6 - log_b (b)
= log_b [(x^2+4)^(-5)*(x)^6/b]

I guess this is the answer.

Answer 2

Hello,

Don't take the log-b b yet.

This means that you divide by log_b b instead of subtracting it which is dividing by 1. So your answer should be: log_b[(x^6)/(x^2+4)^5]

Hope This Helps.