Need help in solving this please:)?

Question

Solve using the quadratic formula:
x^2 – 5x – 1 = -7

Answer 1

First, move the constant to the other side so you have an "= 0" equation:

x^2 - 5x - 1 = -7
x^2 - 5x - 1 + 7 = -7 + 7
x^2 - 5x + 6 = 0

Now you can use the quadratic formula (where a=1, b=-5, and c=6):

x = ( -b +/- sqrt(b^2 - 4ac) ) / 2a
x = ( -(-5) +/- sqrt((-5)^2 - 4*1*6) ) / 2*1
x = ( 5 +/- sqrt(25 - 24) ) / 2
x = ( 5 +/- sqrt(1) ) / 2
x = (5 +/- 1) / 2

x = (5+1)/2 = 6/2 = 3
x = (5-1)/2 = 4/2 = 2

So your answers are x=2, and x=3.

Answer 2

Just so you know it can be solved without quadratic formula:

x^2 -5x +6 = 0
(x-3)(x-2) = 0
x = 3 and 2

Answer 3

You want everything on one side of the equation, so begin by adding 7 to both sidees.
x^2 - 5x + 6 = 0
Now remember that a is the coefficient of x^2 (1 in this case), b is the coefficient of x (-5 in this case), and c is the constant (6 in this case). It is hard to write the formula here, but ...
{-(-5) +/- SQRT[(-5)^2 - 4(1)(6)]} / [2(1)]
= {5 +/- SQRT(25 - 24)} / 2
= [5 +/- SQRT(1)] / 2
= (5 +/- 1) / 2
The "+/-" is telling us how to get two answers from the equation. One answer is
(5 + 1) / 2 = 3
The other answer is
(5 - 1) / 2 = 2

Answer 4

x² – 5x – 1 = -7

Add 7 to both sides

x² – 5x + 6 = 0

ax² + bx + c = 0
x = (-b +- √(b² - 4ac))/2a

x = (5 +- √(25 - 24))/2

x = (5 +- √(1))/2

x = (5 +- 1)/2

Therefore

x = 2, x = 3

Solving for x in this particular case, factoring might have been the easier way.
.

Answer 5

x2 - 5x - 1 = -7
x2 - 5x + 6 = 0

(x-2)(x-3)=0
x=2, x=3


x=2, and x=3, im a honors math student

Answer 6

X^2 - 5X -1 = -7
X^2 - 5X + 6 = 0
(X-2) (X-3) = 0
X = 2, 3

Answer 7

first 2 answers are right x=2 or x=3,first answer should be the best answr i gave him a thumb up,