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4 answers

There are no real zeroes for this polynomial.
Explanation: We want to find if f(x) = 0 for any x in R.
So, is there any x-value which would make 3x4 + 19x2 + 15 = 0?

No. Look at the terms:
3x^4 is either zero or positive.
19x^2 is either zero or positive
15 is...just 15.
So the sum of this expression is always greater than 15. The minimum value occurs when x=0. That min value = 15

2007-05-14 14:42:47 · answer #1 · answered by Anonymous · 1 0

put it in ur graphing calculator. that's how we did it.
click y=
put in the equation
click graph
click trace
then you just go to the left of where it crosses the "x" axis.
then press 2nd trace
go to zero
click enter
click enter
go to the right of where it crosses
push enter again and your answer will be the x answer on the bottom

in this case, there aren't any.

2007-05-14 21:40:20 · answer #2 · answered by imasexybeast 2 · 0 0

Without any calculations each summand of f(x) is positive
so there are NO real roots

2007-05-14 21:42:37 · answer #3 · answered by santmann2002 7 · 1 0

There are none.

2007-05-14 21:38:33 · answer #4 · answered by JoeSchmo5819 4 · 1 0

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