What is the end of this:?

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25x^2 + 9 = 0?

2007-05-14 13:04:05 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

25x^2 + 9 = 0
25x^2 = -9

take square roots each side

(+/-)5x = 3i (where i is the sqaure root of -1)

so x = +3i/5 or -3i/5

2007-05-14 13:10:38 · answer #1 · answered by Glynn R 1 · 1⤊ 0⤋

25x^2 + 9 = 0
minus 9 in each side
25x^2 = -9
divide 25 in each side
x^2 = -9/25
sqaure root -9/25
x = 3i/5

2007-05-14 20:08:19 · answer #2 · answered by jayj 3 · 0⤊ 1⤋

There is no solution to this equation in the real numbers.
If you allow complex numbers:
x = 3i/5 or x = -3i/5

2007-05-14 20:08:10 · answer #3 · answered by Demiurge42 7 · 0⤊ 0⤋

x=3i/5

2007-05-14 20:09:07 · answer #4 · answered by Lexi 2 · 0⤊ 1⤋

no solution

2007-05-14 20:10:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋