suppose that you are an accident investigator and you are asked to figure whether or not the car was speeding up before it crashed through the rail of the bridge and into the mudbank. the speed limit on the bridge is 24m/s. The deep is 4.9m, the distance traveled in the mudbank is 24m. it makes a right triangle with one side is 4.9m and the other side is 24m, hypotenuse is not given. WHat is your conclusion? explain!
2007-05-14 12:51:38 · 2 answers · asked by askative 1 in Science & Mathematics ➔ Physics
The time required to fall 4.9 m is tf = sqrt[2*4.9/g]. The horizontal distance traveled in that time is 24m, so the horizontal velocity was 24/tf
v = 24/sqrt[2*4.9/g]
g = 9.8m/s^2 plug in the numbers and see if the speed comes out more than 24m/s
2007-05-14 12:57:43 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
4.9^2 + 24^2 = c^2
24.01 + 576 = c^2
600.01 = c^2
24.49510 = c
The hypotenuse is about 24.5 feet.
2007-05-14 19:55:59 · answer #2 · answered by Superconductive Magnet 4 · 0⤊ 0⤋