Using Cramer's rule, solve?

Question

2x - y = 4
3x + y - z = 10
y + z = 3

Answer 1

im not sure what cramers rule is but the answer is x=3 y=2 z=1

if you make z the subject in y+z=3 then z=3-y
if you make x the subject in 2x-y=4 then x=2+(y/2)
now you substitute these values of x and z into the equation 3x+y-z, so the equation would be 3[2+(y/2)] + y - [3-y] = 10
the answer comes [y=2]

now substitute this in the remaining equations:
2x-2=4 [x=3]
2+z=3 [z=1]

Answer 2

you are able to not. Cramer's rule demands which you have an identical form of equations as you do variables. you need to remedy the 1st 2 equations applying Cramer's rule and then see if the answer additionally solves the 0.33 equation. x = |-2.....a million| | 5.....3| ------------ |-4.....a million| | 3.....3| = (-6 - 5)/(-12 - 3) = -11/-15 = 11/15 y = |-4....-2| | 3.... 5| ------------ |-4.....a million| | 3.....3| = (-20 + 6)/(-12 - 3) = -14/-15 = 14/15 We get x = 11/15 and y = 14/15 substitute this into the 0.33 equation. We get x + 7y = -4 11/15 + ninety 8/15 = -4 because of the fact the left area is effective and the properly suited area is detrimental. We see that x = 11/15 and y = 14/15 can not remedy the 0.33 equation. So there is no answer.

Answer 3

SOLUTION ::

The determinant form of the given equations is:-

2 -1 0
3 1 -1
0 1 1

FOR 'X' :-

creating a new determinant by replacing the FIRST column of the above determinant :

4 -1 0
10 1 -1
3 1 1

Now divide this new determinant by the first determinant :
We Have:

4/2 -1/-1 0/0
X= 10/3 1/1 1/-1
3/0 1/1 1/1

Solving this determinant : we have:

X= 3

FOR Y :-

creating a new determinant by replacing the SECOND column of the first determinant :

2 4 0
3 10 -1
0 3 1

Now divide this new determinant by the first determinant :
We Have:

2/2 4/-1 0/0
3/3 10/1 -1/-1
0/0 3/1 1/1

Solving this determinant, we have:

Y=2

FOR Z :-

creating a new determinant by replacing the THIRD column of the first determinant :

2 -1 4
3 1 10
0 1 3

Now divide this new determinant by the first determinant :
We Have:

2/2 -1/-1 4/0
3/3 1/1 10/-1
0/0 1/1 3/1

Solving this determinant, we have:

Z=1

Answer 4

First form the determinant of the coefficients of x, y and z:

2....-1.....0
3.....1....-1
0.....1.....1

Then to solve for x, replace the column of x coefficients with the value on the right:

4....-1.....0
10...1.....1
3.....1.....1

Divide this last determinant by the first to get the solution for x. Do the same for y and z

Answer 5

Kramer's Rules:
Always buy fruit from Joe's
If Jerry buys something new, ask him for the old item
Always burst into Jerry's apartment without knocking
Always think of new ideas for inventions and businesses
Always smoke Cubans if you can get them
Name your fighting rooster "Little Jerry"
Always help yourself to whatever food (or anything else) Jerry has in his apartment

Sorry, couldn't resist ;)

Answer 6

type in cramers rule on wikipedia because this problem is too difficult to type

Answer 7

let me see...

3x+y-z=10
2x-y=4
5x-z=14

y+4=2x
y+z=3
5x-3+y=14
5x-3+2x-4=14
7x-7=14
7x=21

x=3
y=2
z=1

sorry. i wish you can understand! i am only a p6 girl and this is the best i can do for you! thx!