I did a lab and in it 0.1M NaOH solution was added and it took 6 drops for the color to change but what if 0.2M of NaOH was used would it need less or more drops for the color change to happen?
2007-05-14 12:18:39 · 4 answers · asked by glance 3 in Science & Mathematics ➔ Chemistry
vol = g / MMW
(1/2)vol = (1/2) g/ MMW
0.5 vol = g / 2 MMW
You'll need half the number of drops. (less)
2007-05-14 13:20:21 · answer #1 · answered by zanekevin13 4 · 0⤊ 2⤋
Less drops. I'm assuming you were adding the NaOH to some sort of color base indicator? .2M means there were more molecules of the NaOH in the solution, which means it would be more basic and therefore cause more change.
2007-05-14 19:23:35 · answer #2 · answered by sam_we_is 2 · 0⤊ 1⤋
It depends on what the color change was for, if it was to show a certain amount of acidity it would take more drops, if it was to show the presense of a base or OH- ions it would take less.
The gentlemen above me are assuming that you were not doing something such as a titration lab.
The higher molarity would cause different affects on different types of labs.
2007-05-14 19:32:23 · answer #3 · answered by Anonymous · 0⤊ 1⤋
It would take half as many drops. What counts is the number of moles of NaOH, and the concentration of 0.2 M has twice as many moles per drop as the 0.1 M solution
2007-05-14 19:30:43 · answer #4 · answered by gp4rts 7 · 0⤊ 1⤋