Math help please?

Question

How do you solve the following?
Simplify

5t-5 (or '5t' minus 5)
Over(like the fraction bar)
t^2-1 (or 't' squared minus one)

Please help me
thanks

thank you sooo much that made a lot of sense.

Answer 1

ok first you have to divide 5 out so it looks like this 5(t-1) then you have to break t^2-1 up like this (t+1)(t-1) and reduce, so your answer is 5/t+1 that is 5 over t+1 as in a fraction Hope you understood this

Answer 2

I think you mean this:

(5t - 5)/(t² - 1)

Factor (t - 1) out of both the numerator and denominator:

((t -1)(5))/((t - 1)(t + 1)

Now cancel out (t - 1) and we are left with:

5 / (t + 1)

.