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Question: (x/(x + 7))/((x - 9)/(x + 7))?



A. -9

B. x/(x - 9)

C. -1/9

D. (x2 - 9x)/(x + 7)2

Thank you!! :):)

2007-05-14 11:43:47 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

B. All that happens is that your (x+7) terms cancel out.

Hint: Write it out as one big fraction and you'll see what happens

2007-05-14 11:46:55 · answer #1 · answered by Lady Geologist 7 · 0 0

This is equal to x/x+7 times x+7/x+9. The x+7's cancel out, leaveing you with b, x/x+9.

2007-05-14 18:47:21 · answer #2 · answered by Duncan C 1 · 0 0

x/(x+7) (x+7)/(x-9) = x/(x-9)
its B

2007-05-14 18:49:20 · answer #3 · answered by hacker_lexy 3 · 0 0

Flip the second fraction, and the x+7's will cross cancel leaving you with answer b.

(x/(x+7)/(x-9)/(x+7)
(x/(x+7)*(x+7)/(x-9)
x/(x-9)

2007-05-14 18:47:16 · answer #4 · answered by danjlil_43515 4 · 0 0

Assuming that you simply are looking to reduce the equation

The Answer is B: x/(x-9).

How to get there (this is the long way, but it's thorough):

Look at the equation like this:

Make x+7 = y
Make x-9 = z

So now your equation is
(x/y)/(z/y) = 1

Balance both side of the equation by multiplying both sides by (z/y). This gives you:

x/y = z/y

Multiply both sides by "y". This gives you:

x = z

Now divide both sides by "z" to get everything back to the left of the equation.

x/z = 1

So, since z=x-9, then the answer is B: x/(x-9)

2007-05-14 19:00:41 · answer #5 · answered by cardcomedy 1 · 0 0

Answer B is correct because the x-7 all cancel out to form answer B

2007-05-14 18:49:05 · answer #6 · answered by Yueqing 2 · 0 0

(x/(x + 7))/((x - 9)/(x + 7))
x(x+7)/((x+7)(x-9)
x/(x-9)

B. x/(x - 9) is correct

2007-05-14 18:48:09 · answer #7 · answered by yupchagee 7 · 0 0

B.x(x-9)

2007-05-14 18:51:16 · answer #8 · answered by hannah banana 4 · 0 0

Would you really like some one else doing your school work?

2007-05-14 18:49:47 · answer #9 · answered by yasses 4 · 0 0

look i pass sol math algebra

2007-05-14 18:47:19 · answer #10 · answered by $Goldmoney$ 1 · 0 0

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