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Hi,

I have questions regarding these problems. I have tried to solve them without any success. If you’re adept in this area of physics, please try to provide some help.

1. The amusement park ride is the wave swings, or an upside down carousel wheel that spins people around. The period is 6 seconds; the radius is 10 m, and the angle of the chains while in motion is 60 degrees. The question: based on the angle, how much is the tension in each of the 4 chains holding you up? I am very bad at drawing vectors and making angles, and I got 200 N, which is most likely wrong.

These questions are in relation to a freefall ride, similar to the Tower of Terror at Disney World. You’re lifted up really high into the air for this elevator and dropped down several times. The total upward displacement is 62.484 m. This is the only information we’re provided.

2. What is your maximum velocity on the ride (occurs at 1/3 of the displacement)? I used the 4 kinematic equations, and I used the

2007-05-14 10:56:42 · 2 answers · asked by kiki 1 in Science & Mathematics Physics

2 answers

for number 1 compute the angular acceleration in the horizontal that balances the weight "lifted" to an angle of 60 degrees

The sum of the tensions will be
m*sqrt(g+w^2*R)
since yo udidn't provide the mass I can't compute it. The rpm are 10, which translates to 1.0472 rad/sec.

2. Assuming no friction, you are on the right track that the speed will be related to the PE conversin to kinetic
m*g*h=.5*m*v^2
or
v=sqrt(2*g*h)
at 1/3 into the fall, h=62.484/3 m

j

2007-05-14 11:12:33 · answer #1 · answered by odu83 7 · 0 0

If the boy drops the ball to free fall, the following should apply Initial Velocity is 0 m/s Final Velocity is 14.7 m/s Acceleration is (gravity =9.8 m/s2) distance = 1/2 * gt^2 = 1/2 * 9.8 * 4 = 19.6 m If the boy power throws the ball with initial speed of 14.7 m/s, then the following should apply d = Vi *t + 1/2 gt^2 d= 14.7*2 + 1/2*9.8*4 = 49 m

2016-05-18 01:38:30 · answer #2 · answered by ? 3 · 0 0

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