Probability that when rolling two dice that you will have a sum greater than 5?

Answer 1

when you rolling two dice you will get 36 possile outcomes
which are ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 1 , 4 ) , ( 1 , 5 ) , ( 1 , 6 )
( 2 , 1) , ( 2 ,2) , ( 2 , 3 ) , ( 2 , 4 ) , ( 2 , 5 ) , ( 2 , 6 )
( 3 , 1) , (3,2) , (3 , 3 ) , ( 3, 4 ) , ( 3 , 5 ) , (3 , 6 )
( 4 , 1) , ( 4 ,2) , (4 , 3 ) , (4 , 4 ) , ( 4 , 5 ) , ( 4 , 6 )
(5 , 1) , ( 5 ,2) , (5 , 3 ) , ( 5 , 4 ) , ( 5 , 5 ) , ( 5, 6 )
( 6, 1) , (6 ,2) , ( 6 , 3 ) , ( 6 , 4 ) , (6 , 5 ) , ( 6 , 6 )

the sum greater than 5 when you get
( 1 , 5 ) , ( 1 , 6 ) , ( 2 , 4 ) , ( 2 , 5 ) , ( 2 , 6 )
(3 , 3 ) , ( 3, 4 ) , ( 3 , 5 ) , (3 , 6 ) ( 4 ,2) , (4 , 3 )
(4 , 4 ) , ( 4 , 5 ) , ( 4 , 6 )(5 , 1) , ( 5 ,2) , (5 , 3 )
( 5 , 4 ) , ( 5 , 5 ) , ( 5, 6 ), ( 6, 1) , (6 ,2) , ( 6 , 3 )
( 6 , 4 ) , (6 , 5 ) , ( 6 , 6 )
which are 26 outcome
then the probability to get number greater than 5 = 26 / 36
= 13 /18

Answer 2

Out of all the possible 6*6 = 36 rolls you could make, the only pairs that will give you a sum greater than 5 are:
(6,6), (6,5), (6,4), (6,3), (6,2), (6,1)
(5,5), (5,4), (5,3), (5,2), (5,1)
(4,4), (4,3), (4,2)
(3,3)

These are 15 of these pairs. 4 of them have the same value on both dice. Others can come up one of two different ways (e.g. "6,5" could be getting a 6 on the first die and 5 on the second, or vice versa). So the total number of winning roles is 4 + 11(2) = 26.

The probability then is 26/36 = 13/18

Answer 3

5/36 ok i think I ought to describe how I have been given the respond simply by fact it style of feels lots of people who're answering this question have been given it incorrect. Altogether you have 36 different opportunities while rolling 2 cube a million/a million a million/2 a million/3 a million/4 a million/5 a million/6 2/a million ...... etc yet out of all 36 there are basically 5 that have a sum of 6 a million/5 2/4 3/3 4/2 5/a million

Answer 4

There are 36 possible combinations altogether. Of these, the following sum to 5 or less:

11,12,13,14,21,22,23,31,32,41

...i.e. 10 combinations. So the probability is 26/36 (=13/18) that the sum is GREATER than 5.

Answer 5

You have about a 72% chance of rolling a sum greater than five.

Of the 36 possibilities, 26 of them would show a sum greater than five.

Answer 6

Let's state all the possibilities
Let x = # rolled from first die
Let y = # rolled from second die
We will list all pairs such that (x+y)>5

(x,y)

(1,5)(1,6)
(2,4)(2,5)(2,6)
(3,3)(3,4)(3,5)(3,6)
(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

So there is a total of 26 possibilites. The total number of combinations when you roll 2 dice is 36

Therefore the probabilty we want = 26/36
=13/18

Answer 7

If the 2 dice are different
out of 36
(1,5),(1,6 )
(2,4)......(2,6),
(3,3)........(3,6),
(4,2)........(4,6),
(5,1)........(5,6),
(6,1)........(6,6), the total number is 26
then the Probability = 26/36=13/18
If the 2 dice are similar
out of 21
(1,5),(1,6 )
(2,4).(2,5),(2,6),
(3,3)(3,4),.(3,5)(3,6),
(4,4),(4,5),(4,6),
(5,5),(5,6),
(6,6), the total number is 15
then the Probability = 15/21=5/7

Answer 8

you would have to calculate all the possibilities subtract the ones that are less than five and put that over the total number of posibilities