i have 2 fractions questions?

Question

(1) 3y = 4/5

(2) 2T = 4/7

(3) 2T = 2/3

(4) 4/5 = 15

(5) 6b/9 = 15

Please explain and check so i will know how to do it well u do not have to do all but i will give best answer to who ever does the problems (all five) and has them right

Look Mr. Cho Seun Hui, this is that young lady's sister. I'm guessing your a child. Because an adult would have more sense than to say something so ignorant. People make mistakes on the computer, it's obvious what the question was. So that comment that you pulled out of your behind... you need to turn into some sense. I appreciate everyone else's assistance with the math. It's been about 10 years since I've done this type of math.

gjmb1960 dont wonder how many points ill tell u none

4/5D= 15 IS WHAT I MEANT TO SAY

Answer 1

(1) 3y = 4/5
right now, you're multiplying 3 and y. To get y alone, you need to do the oppositve thing to y, so you divide both sides by 3.

y = (4/5)/3
y = (4/5)*(1/3) = 4/15

To check, just put that back in the original question.
3y = 4/5?
3(4/15) = 4/5?
3(4/3*5) = 4/5?
3(1/3)(4/5) = 4/5?
4/5 = 4/5 TRUE

(2) 2T = 4/7
Again, you have 2 times T. To get T alone, divide by 2.
T = (4/7)/2 = (4/7)(1/2) = 2/7

You can check it yourself.

(3) 2T = 2/3
This one is almost exactly the same as #2.
T = 1/3

(4) 4/5D = 15
Multiply both sides by 5...
4D = 75
Divide both sides by 4...
D = 75/4

(5) 6b/9 = 15
Right now, you have 6b divide by 9. Get the 6b alone by multiplying both sides by 9.

6b = 9*15
6b = 135

Now, you have 6 times b. To get the b alone, divide by 6.

6b = 135
b = 135/6 = (3*45)/(3*2) = 45/2

Answer 2

1) 3y=4/5 divide by 3 on both sides y=4/15
2)2T=4/7 divide by 2 on both sides T=2/7
3)2T=2/3 divide by 2 on both sides T=1/3
4) 4/5=15 your missing the variable, but I'll assume you ment 4x/5=15 in this case you will multiply by the recipricle of the fraction 4/5 which is 5/4 to both sides. x=75/4
5) 6b/9=15 same as last problem. b=45/2

Answer 3

ok first you need to learn how to count

there are 5 problems, not 2 as you mentioned in the question....

(1) 3y = 4/5
y = (4/5) / 3 = 4/(3*5) = 4/15

2) 2T = 4/7
T = (4/7) / 2 = 4/(2*7) = 2/7

(3) 2T = 2/3
T = (2/3) / 2 = 2/(2*3) = 1/3

(4) 4/5 = 15
?????? nothing to solve.

(5) 6b/9 = 15
=>
6b = 15 * 9
=>
b = (15 * 9) / 6 = (15*3)/2 = 45/2

.
i am wondering now how many points i will get 1, 10 ? 2 ? 3 ???
.

Answer 4

1. 3y=4/5
3y/3=4/5 / 3=
y=4/5 *1/3=4/15

2. 2T=4/7
2T/2=4/7 / 2
T= 4/7 / 2
T=4/7 x 1/2=4/14=2/7

3. 2T=2/3
2T/2= 2/3 / 2
T=2/3 / 2
T= 2/3 * 1/2= 1/3

4. 4/5x=15
4/5x / 5/4 = 15/1 * 5/4
x=75/4=18 3/4

5. 6b/9=15
multiply all by 9
6b=135
6b/6=135/6
b=22 3/6=22 1/2

Answer 5

1. multiply both sides by 1/3

3y = 4/5
y = (4/5)(1/3) = 4/15

2. Multiply both sides by 1/2

2t = 4/7
t = (4/7)(1/2) note that the 4 and 2 reduce so = 2/7

3. Multiply both sides by 1/2

2t = 2/3
t = (2/3)(1/2) note that the 2's cancel so = 1/3

4. 4/5 not equal to 15 (missing variable)

5. 6b/9 = 15 note that 6/9 reduces to 2/3

6b/9 = 15

2b/3 = 15 multiply both sides by 3/2

b = (15/1)(3/2) = 45/2 = 22 1/2 if you need mixed number

Answer 6

1. multiply both sides by 1/3

3y = 4/5
y = (4/5)(1/3) = 4/15

2. Multiply both sides by 1/2

2t = 4/7
t = (4/7)(1/2) note that the 4 and 2 reduce so = 2/7

3. Multiply both sides by 1/2

2t = 2/3
t = (2/3)(1/2) note that the 2's cancel so = 1/3

4. 4/5 not equal to 15 (missing variable)

5. 6b/9 = 15 note that 6/9 reduces to 2/3

6b/9 = 15

2b/3 = 15 multiply both sides by 3/2

b = (15/1)(3/2) = 45/2 = 22 1/2 if you need mixed number

Answer 7

Hey man, it's best you learn the idea behind what's going on...then you can do any problem of this type by yourself.

When you have any variable, lets say x for example, with a constant (a number) in front of it, and you want to solve for x, just remember that you can do anything to one side of an equation if you do the same thing to the other side (which I'm sure you know), so for example:
3x=6
If we want to find out what x equals all we have to do is divide both sides of the equation by 3 to get rid of the constant in front of the x:
3x/3=6/3
x=2
The variable can be any letter, it doesn't matter.

The second thing you have to remember is that any fraction divided by another number or fraction is the same thing as the fraction multiplied by the reciprical of whatever you are dividing it by. This sounds complicated but really it's not...for example:
3/4 divided by 5 is the same as multiplying 3/4 by the reciprical of 5: (keep in mind that 5 is the same as 5/1)
The reciprical is obtained by flipping the fraction:
so the reciprical of 5 (which is really 5/1) is 1/5
so:
3/4 divided by 5 is the same as:
3/4 multiplied by 1/5 (which is easy to solve)
(3/4)(1/5)=3/20

So lets try and put those ideas together and solve an equation:

3c/2+2/7=4/7
So the first thing we want to do is get the variables on one side and the constants without variables (just numbers) on the other side. Step one would be to subract 2/7 on the left side (and if we do that we have to do the same to the right side):
3c/2+2/7-2/7=4/7-2/7 (so the 2/7 cancels out on the left side and 4/7-2/7 appears on the right.)
so now we get:
3c/2=2/7
Now we have to isolate the c variable to solve for c..to do that we do the same thing as we did for the 3x=6 example:
3c/2 divided by 3/2=2/7 divided by 3/2 (we divided the left side by 3/2 to get rid of the constant in front of the c so we had to do the same to the right side)
*remeber 3c/2 is the same as (3/2) times c or (3/2)c (what I'm trying to say is that 3/2 is a constant, just like 3 was for the 3x=6 example, and we can get rid of it in the exact same way)*
so we get:
c=2/7 divided by 3/2
If you remember a fraction divided by another fraction is the same as the fraction multiplied by the reciprical of the fraction you were dividing by:
so 2/7 divided by 3/2 is the same as:
2/7 multiplied by 2/3
which is:
(2/7)(2/3)=4/21
so:
c=4/21

As long as you understand what's going on you can solve any problem like this. It's honestly more important to understand the concept than anything else. Good luck! Math is actually really cool!

Answer 8

For #1, multiply both sides by the denominator 5 to give 15y = 4. Then divide by the 15 to get y = 4/15. Do the next two the same way. You can't do #4 the way you wrote it. In #5, multiply both sides by 9 to give 6b = 135. Then divide both sides by 6 to get your answer.

Answer 9

1. divide both sides by 3. y=(4/5)/3= 4/5*1/3=4/15
dividing (a/b)/(c/d)=(a/b)*(d/c). 3=3/1
2. divide both sides by 2. t=(4/5)/2=(4/5)*(1/2)=4/10=2/5
3. divide both sides by 2. t=(2/3)/2=(2/3)*(1/2)=2/6=1/3
4. I'm not sure what the question is here
5. multiply both sides by 9. 6b=15(9)=135. divide both sides by 6. b=135/6=22.5

Answer 10

Problem 1
y = 4/15
You divide both sides of the equation by 3
Problem 2
T = 2/7
You divide both sides of the equation by 2
Probem 3
T = 1/3
You divide both sides of the equation by 2
Problem 4
4/5 = 15 is false. Did you forget a variable?
Problem 5
b = 45/2.
You divide both sides of the equation by 9/6. Then divide the 6 and the 15 by their greatest common divisor, which is 3.