Spread the word. I won't be buying any all week! Make them lower gas prices!!!
2007-05-14 08:17:43 · 8 answers · asked by kyeann 5 in News & Events ➔ Current Events
How can it be a hoax??? If we refuse to pay their prices, they will have to lower them, duh!!
2007-05-14 08:29:29 · update #1
Yes we will have to drive as little as possible. Not driving kinda goes along with not buying gas. I won't be leaving town and if I can I'll ride my bike.
2007-05-14 08:35:11 · update #2
At least you are thinking beyond the hoax. Just use less of it. Gas is a barrier because we are demanding more than the market can supply. The high price is a signal for us to use less and quit buying F 350 turbo diesel trucks to drive us to the mall.
2007-05-14 08:42:30 · answer #1 · answered by trigunmarksman 6 · 2⤊ 0⤋
Stop thinking gas boycott. The oil companies couldn't care less. If you use your car on Tuesday at all, the gas you don't buy tomorrow you'll buy today or Wednesday. Start thinking driving boycott for a couple of days and prices will go down...until you start driving again. The only one you'll be hurting with your gas boycott will be your local small businessman who make nearly as much selling food, soda, etc.
2007-05-14 15:29:42 · answer #2 · answered by Anonymous · 0⤊ 2⤋
I'll buy some... I LOVE being robbed!!!
Thanks for the reminder.
2007-05-14 15:23:51 · answer #3 · answered by Klaatu verata nichto 3 · 1⤊ 1⤋
Its a H O A X
google it
2007-05-14 15:25:02 · answer #4 · answered by jon_mac_usa_007 7 · 0⤊ 2⤋
Blah blah blah blah. Same old b.s. from same old unthinking people. Supply and demand. Supply and demand. Supply and demand. Supply and demand. Supply and demand. Sheesh.
2007-05-14 15:21:52 · answer #5 · answered by chumley 4 · 1⤊ 3⤋
let's show them, don't gas up tommorow.
2007-05-14 18:02:07 · answer #6 · answered by Anonymous · 2⤊ 0⤋
I almost forgot, thanks for the reminder
2007-05-14 15:21:01 · answer #7 · answered by Anonymous · 2⤊ 0⤋
oh yeah! thanks for reminding me!!!
2007-05-14 15:19:31 · answer #8 · answered by itsjustme 3 · 2⤊ 0⤋