2007-05-14 07:32:50 · 12 answers · asked by that guy 1 in Science & Mathematics ➔ Physics
i think the bullet would leave the barrell.
2007-05-14 07:37:50 · answer #1 · answered by b 4 · 0⤊ 0⤋
If you are travelling the speed of a bullet and then shoot a gun, the bullet will still shoot up ahead of you. That is because it is forced forward from where you are. Note that your velocity would most likely slow down from the force of the shot and the velocity of the bullet would slow down due to wind resistance.
2007-05-14 07:50:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
No. Think about our moon rocket ship. It is made up of many stages. When then the button,or first stage, is used up, it falls away and the second stage starts up. When this happens the speed of the first stage is added to the speed of the second stage. This goes on until the final stage is fired. As of May 14, 2007 no single rocket can leave the earth and go to the moon. Stage rockets are the only way (unless you leave from orbit).Your bullet would travel out of the barrel. Hope this help.
2007-05-14 07:51:04 · answer #3 · answered by batman1943 1 · 0⤊ 0⤋
No. The bullet in the gun has the same initial Velocity that you do since it's traveling with you. When you fire the gun, it will leave the barrel with a velocity equal to your initial velocity plus the gun's normal muzzel velocity.
2007-05-14 07:36:51 · answer #4 · answered by Scott W 3 · 0⤊ 0⤋
No. It will be ejected from the barrel at the sum of its normal velocity plus the velocity of the gun. This is the velocity addition rule of Newtonian physics; it is not valid for objects traveling near the speed of light, for which relativistic physics must be used.
2007-05-14 07:38:24 · answer #5 · answered by Anonymous · 1⤊ 0⤋
the first gut is right but not only that, imagine that you shoot the gun backward (in the opposite direction that you are traveling. you will still see the bullet leave your gun at its normal speed but the ground observer will see it fall strait to the ground.
2007-05-14 07:40:15 · answer #6 · answered by karl k 6 · 1⤊ 0⤋
No. The explosion will add velocity to the bullet, not set its velocity. The bullet will travel that much faster.
2007-05-14 07:37:47 · answer #7 · answered by Matthew C 1 · 0⤊ 0⤋
No, it would go double its usual speed (if you ignore wind resistance) since the explosion that powers it will still create the same amount of energy to propel the bullet.
2007-05-14 07:37:14 · answer #8 · answered by Michael H 2 · 0⤊ 0⤋
no it would come out at twice the velocity but that's without wind resistance so probably just under twice but if you started of standing still and the accelerated at the same speed it would.
not sure how that would be possible though
2007-05-14 07:42:43 · answer #9 · answered by Anonymous · 0⤊ 0⤋
No, it will still exit the barrel with it's nominal muzzle velocity, so it's total velocity will be twice muzzle velocity (relative to a stationary ground observer, or stationary target).
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2007-05-14 07:36:28 · answer #10 · answered by tlbs101 7 · 3⤊ 0⤋