PLease Need Help With Math?

Question

1. (-r√r^2s)(-s√r^2s)
A.-r^3s^2
B.r^3s^2
C.-r^2s√s
D.r^3s^3

2. √27 x √3n x √5n
A. 3n√45
B. 9n√15
C. 6n√5
D. 9n√5

Answer 1

1. (-r√r^2s)(-s√r^2s)
= rs.r^2s = r^3s^2

B is the right answer.

2.√27 x √3n x √5n

= 3√3 x √3n x √5n
= 3 x 3 x n x √5
= 9n√5

D is the answer

Answer 2

1. (-r√r^2s)(-s√r^2s)

Simplify each value in the parentheses

(-r X √r^2s) (-s X √r^2s)

(-r X r√s)
You can extract r^2.. it will become r√s
(-s X r√s)
You can also extract r^2.. it will also become r√s

(-r X r√s)(-s X r√s)
(-r^2 X √s)(-rs X √s) Combine variables with same degrees
r^3 X s X (√s X √s)
r^3 X s X (√s^2)
r^3 X s X s
r^3 X s^2
r^3s^2 ---------> B.

2. √27 x √3n x √5n

3√3 X √3n X √5n

3√9 X 5 X n^2 ------------>We separate 9 and 5 because 9 is a perfect square; it can already be extracted.

3 X 3 X n √5
We were able to extract 3 and n.

9n√5 ------------> D.

Answer 3

2 D.

I am not sure about #1, it is tough to follow the notation. Is that r to the "2s" power or just r-squared times s?

Answer 4

1: B, right away the negatives cancel, there is r^3 after performing the square root functions along with s*√s *√s

Answer 5

http://www.coolmath.com
http://www.purplemath.com

Answer 6

wtf...damn..