Factor: x3+8x2+15x
(It is not x times 3 it is x to the third...and the x2 is actually x squared.)
2007-05-14 06:19:47 · 9 answers · asked by Peeko 2 in Science & Mathematics ➔ Mathematics
x³ + 8x² + 15x =
x(x² + 8x + 15) =
x(x² + 5x + 3x + 15) =
x[x(x + 5) + 3(x + 5)] =
x(x + 3)(x + 5)
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2007-05-14 07:04:56 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
First factor out anything that is common
x^3 + 8x^2 + 15x (one x is common so factor it out)
x(x^2 + 8x + 15) (notice that the a position is one, so find two numbers which multiplied equal 15 but added equal 8:
15
1 * 15 = 15 ; 1 + 15 = 16 not corect
3 * 5 = 15 ; 3 + 5 = 8 correct
x(x + 3)(x + 5)
2007-05-14 13:25:06 · answer #2 · answered by Poetland 6 · 0⤊ 0⤋
x^3 + 8x^2 + 15x
= x(x^2 + 8x + 15)
= x(x + 5) (x + 3)
2007-05-14 13:25:51 · answer #3 · answered by Mehn 3 · 0⤊ 0⤋
x3+8x2+15x
=x(x^2+8x+15)
=x(x+3)(x+5)
Trick was to get it down to a quadratic
2007-05-14 13:23:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
u can denot power by usin ^.. x^3 mean x to the power 3
x^3+8x^2+15x
=x(x^2 + 8x + 15)
=x(x^2 + 3x + 5x + 15)
=x{ x(x+3) + 5(x+3)}
=x(x+3)(x+5)
2007-05-14 13:24:24 · answer #5 · answered by Rakesh M 1 · 0⤊ 0⤋
Here is the solution:
x^3+8x^2+15x
x(x^2+8x+15)
x(x+5)(x+3)
2007-05-14 13:23:08 · answer #6 · answered by Sinatra 2 · 0⤊ 0⤋
x(x^2+8x + 15)..... taking x common and then factorising by splitting the middle term we get factors as
x (x+5) (x+3)
2007-05-14 13:24:38 · answer #7 · answered by macline k 2 · 0⤊ 0⤋
x(x2+8x+15)
x(x+3)(x+5)
2007-05-14 13:22:33 · answer #8 · answered by qweezyq 2 · 0⤊ 0⤋
take out an x and do it normal
x(x+3)(x+5)
2007-05-14 13:22:36 · answer #9 · answered by rogue chedder 4 · 0⤊ 0⤋