Algebra Help?

Question

Write the equation of the line passing through (1, 5) and (7, 5).

Answer 1

1. Find the slope, which is (y2-y1)/(x2-x1). In your case, this would equal 0.
2. Insert slope (slope=m) into this equation: y=mx+b. In your case, this becomes y=b.
3. Take a point and insert the y-value in for y, and the x-value in for x. In your case, 5=b.
4. Solve for b. In your case, b=5.
5. Plug slope and b into y=mx+b. In your case, y=0*x+b or y=5.

Your equation is y=5.

Answer 2

y=5

Answer 3

To find the equation of a line passing through two points you need to first find the slope

m = (y2 - y1) / (x2 - x1)

m = (5 - 5) / (1 - 7) = 0/(-6) = 0

Since the slope equals zero it must be a horizontal line passing through the y value always,

so y = 5 is the equation of the line

Answer 4

If this is a straight line, the equation will be simply y = 5, indicating a horizontal straight line passing through the y axis at 5.
If it's an equation for a curve you are looking for, you will need to determine what sort of curve it is, and provide at least 1 more reference point to be able to determine the more complex equation describing the curve.

Answer 5

You first need to find the slope by subrtacting your y's over your x's which gives you 0/6 which is 0.
Then you have to put it in point slope form which is y-y1=m(x-x1) using either point which gives you y-5=0(x-1) and then solve for y which puts it in slope intercept form which gives you y=5

Answer 6

y=mx + b

m=slope
b=the y intercept

The y-intercept is obviously 5, seeings how both vectors have the same number for y.

The slope is 0/4, change in y over change in x.

The line is horizontal, since the change in y is 0.

Therefore, your equation is y=5.

Answer 7

m = 0
y = 5 is required equation

Answer 8

0x+y=5