solve the equation and show working
2007-05-14 04:03:16 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2 - x = 0 => x(x-1) =0 => x=0 or x =1.
2007-05-14 04:39:16 · answer #1 · answered by Steiner 7 · 0⤊ 0⤋
x^2 - x = 0
=> x(x - 1) = 0
=> x = 0 or x - 1 = 0 => x = 1
2007-05-14 04:08:20 · answer #2 · answered by raja 3 · 1⤊ 0⤋
Start by getting a common denominator: Multiply x/5 by x/x Multiply 2/x by 5/5 You end up with x^2/5x - 10/5x = 3 Now that you have a common denominator on the left side, you can subtract. x^2/5x - 10/5x = (x^2-10)/5x Multiply each side by 5x. This leaves you with: x^2-10 = 15x Subtract 15 x from both sides. You get x^2-15x-10 = 0. You can't factor this so you have to use the quadratic formula to find the values of x.
2016-05-17 22:27:57 · answer #3 · answered by madeline 4 · 0⤊ 0⤋
x(x-1) = 0, is true when x =0 or x =1.
2007-05-14 04:10:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x² - x = 0
x(x - 1) = 0
x = 0 or (x-1) = 0
Solutions are thus: x=0 or x = 1
2007-05-14 04:06:04 · answer #5 · answered by MamaMia © 7 · 1⤊ 0⤋
this implies that x(x-1)=0
so, x=0 and x-1=0 which means x=1 also.
2007-05-14 04:10:09 · answer #6 · answered by thenarcolepticone 3 · 1⤊ 0⤋
x^2-x=0 answer is x=0 or x=1
x(x-1)=0
x=0
x-1=0
x-1+1=0+1
x=1
2007-05-14 04:24:01 · answer #7 · answered by Anonymous · 0⤊ 0⤋
x^2-x=0 answer is x=0 or x=1
x(x-1)=0
x=0
x-1=0
x-1+1=0+1
x=1
2007-05-14 04:17:41 · answer #8 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
X^2-x=0 Add x to both sides:
x^2=x divide both sides by x
x=1
Answer.
2007-05-14 04:12:20 · answer #9 · answered by Dave B. 4 · 0⤊ 0⤋
x^2 -x=0
x(x-1)=0
then x=0
or x-1=0 then x=1
{1,0}
2007-05-14 04:07:37 · answer #10 · answered by Mohammed R 1 · 1⤊ 0⤋