can some on explain to me the diffrence from ...?

Question

this is a trigernomtry question

sin = opposite/hypotenuse

cos = adjacent/hypotenuse

tan = opposite/adjacent

Answer 1

Draw a right triangle.
One angle is the right angle, or 90 degrees.

Choose one of the other two angles, and call it theta degrees.

From that angle, the side opposite to it is called "opposite".
The hypotenuse is called "hypotenuse." The remaining side is called "adjacent."

The ratio of the lengths of opposite/hypotenuse defines the value of a function called sine for the angle theta.

The ratio of the lengths of adjacent/hypotenuse defines the value of a function called cosine for the angle theta.

The ratio of the lengths of opposite/adjacent defines the value of a function called tangent for the angle theta.

Answer 2

If you draw a right angled triangle ABC with the right angle at A, then the hypotenuse is the longest side BC, opposite A.

Referring the the angle B:
sin(B) = AC (opposite B) / BC (hypotenuse)
cos(B) = BA (adjacent to B) / BC (hypotenuse)
tan(B) = AC (opposite B) / BA (adjacent to B).

For angle C, the hypotenuse is still BC, but the adjacent side is AC, and the opposite side is BA. In terms of 'adjacent' and 'opposite', the formulae remain the same, but in terms of sides, they are different.
sin(C) = AB / BC
cos(C) = AC / BC
tan(C) = AB / AC.

Answer 3

These partial equations refer to a right triangle.

Sin by itself has no meaning, you are referring to the sine of an angle such as sin (x), x being the angle in degrees or in radians.

A right triangle has three angles, one of which is 90 degrees. The equations are for the other two angles.

Rather than opposite or adjacent, you are referring to side opposite the angle or side adjacent the angle.

The hypotenuse refers to the side opposite the 90 degree angle.

I hope this helps. If it doesn't, please ask with some specific problems to solve.
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Answer 4

erm, what is your question? these are basically just trigonometry formulas. okay, for example, take

triangle ABC (imagine it!)
where the angle at B is 90 deg (a right angle triangle)
AB is... say, 2.
and BC is... say, 3
so the hypothenus would be {root[(2^2) + (3^2)]} right?
so anyway its basically [root 13]

so say the angle at A is... x

sin x = 3/[root 13] (opposite/hypothenus)
cos x = 2/[root 13] (adjacent / hypothenus)
tan x = 3/2 (opposite/adjacent)

so from here, you can see that tan x actually is [sin x / cos x]

because (3/[root 13]) / (2/[root 13]) = 3/2!

anyway, im not sure what ure asking but i hope this helps you to understand better.

cheers

Answer 5

it's from Pythagore's theoreme andthese are true for a right angle triangle only.

sin = opp. / hyp
cos = adj / hyp

tan = sin / cos = opp / adj

Answer 6

There's information missing. You really need a diagram, so look here http://id.mind.net/~zona/mmts/trigonometryRealms/introduction/rightTriangle/trigRightTriangle.html