2007-05-14 02:38:07 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
the chance that 2 people do not have the same birthday
is 364 chances out of 365 days.
for 3 people not to have the same birthday:
(364/365)(363/365)
so, for 23 people not to have the same birthday, the chances are:
(364/365)(363/365)(362/364).....(343/365)
if you multiply it out, it comes out to about 49%.
so, the chances that 2 out of 23 people WILL have the
same birthday is 1-.49 = about 51%
strange, but true!
2007-05-14 02:52:02 · answer #1 · answered by jaybee 4 · 6⤊ 1⤋
I believe jaybee has the best answer but only considering that the date in question (birthday) is not specific in which year these birthdays occur. 2 people having the same birthday in the same year would not be as likely.
2007-05-14 03:26:16 · answer #2 · answered by Tim C 4 · 0⤊ 0⤋
Better than 50%
http://en.wikipedia.org/wiki/Birthday_paradox
2007-05-14 02:53:06 · answer #3 · answered by Gene 7 · 1⤊ 0⤋
1 / 365 * 2 / 23
= 2 / 8395
2007-05-14 02:47:45 · answer #4 · answered by Wooly 4 · 0⤊ 4⤋
jaybee is exactly correct. No idea why someone gave his answer a thumbs-down rating.
2007-05-14 03:03:16 · answer #5 · answered by Astronomer1980 3 · 1⤊ 0⤋
somewhere around 50%
2007-05-14 09:46:24 · answer #6 · answered by Mr. Smith 5 · 0⤊ 0⤋
1 in 10,000
2007-05-14 02:43:04 · answer #7 · answered by Daniel P 2 · 0⤊ 5⤋
51.264% to be exact.
2007-05-14 05:05:42 · answer #8 · answered by Wedge 4 · 0⤊ 0⤋