Simplify: (x^2+4x-5) / (2x^2-3x+1) - x/(2x-1)?

Answer 1

(x^2+4x-5) / (2x^2-3x+1) - x/(2x-1)

Factor the parts of the first fraction:
x^2 + 4x - 5 = (x + 5)(x - 1)
2x^2 - 3x + 1 = (2x - 1)(x - 1)

So, the first fraction becomes:
(x + 5)(x - 1) / (2x - 1)(x - 1)

which simplifies to

(x + 5) / (2x - 1)

Now you have:
(x + 5) / (2x - 1) - x / (2x -1)
= (x + 5 - x) / (2x - 1)
= 5 / (2x - 1)

Answer 2

#a million) that's a doozy. With each and every each and every coin turn, there are merely 2 opportunities, and you multiply all of them jointly to get all achieveable mixtures: 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 2¹º = 1024 Now, i haven't look at attainable e book in years, yet I do undergo in ideas that the blend of heads on no account springing up is: 10!/10! = a million ... springing up as quickly as: 10!/(a million! x 9!) = 10 ... springing up two times: 10!/(2! x 8!) = 40 5 so the opportunities of two heads or much less = (a million + 10 + 40 5)/1024 = fifty six/1024 = 7/128 #2) sorry, no longer in my adventure #3) the 2d by-product will answer that: y = x³ - x² + 3x + a million 1st by-product: y' = 3x² - 2x +3 2d by-product: y" = 6x - 2 ... whilst y" = 0, x = a million/3. Plugging into the 1st by-product: y' = 3(a million/3)² - 2(a million/3) +3 = (a million/3) - (2/3) + (9/3) = 8/3 ... and that i'm off to mattress. reliable success with something...

Answer 3

(x^2+4x-5) / (2x^2-3x+1) - x/(2x-1)

Factor the numerator and the denominator.

((x+5)(x-1))/((2x-1)(x-1)) - x/(2x-1)

Cancel the (x-1) in the numerator and the denominator.
(x + 5)/((2x - 1) - x/(2x - 1)

Now combine terms

(x + 5 - x)/(2x-1)

Thus

5/(2x - 1)
.

Answer 4

(x^2+4x-5) / (2x^2-3x+1) - x/(2x-1)
=[(x+5)(x-1)] / [(2x-1)(x-1)] -x/(2x-1)
=[(x+5) / (2x-1) - x/(2x-1)
=(x+5-x) / (2x-1)
=5/(2x-1)

Answer 5

= [(x + 5).(x - 1)] / [(2x - 1).(x - 1)] - x / (2x - 1)
= (x + 5) / (2x - 1) - x / (2x - 1)
= 5 / (2x - 1)

Answer 6

[(x - 1)(x + 5)]/[(x - 1)(2x - 1)] - x/(2x -1) =
(x + 5)/(2x - 1) - x/(2x - 1) = 5/(2x - 1)