Calculate the average mass density of the earth. The earth's mass is 5.98x10 to the power of24kg and it's radi

Question

Calculate the average mass density of the earth. The earth's mass is 5.98x10 to the power of24kg and it's radius is 0.38x10 to the power of 6 m.?

Answer 1

Your value of the mass of the earth is accurate. The radius of the earth is approximately 6378km or 6.4*10^6m.

From memory the actual density is about 5500kg/m^3. The earth the densest planet in the solar system.

Answer 2

Density Of The Earth

Answer 3

The mass of the earth was not known by "ancient" astronomers (unless you consider 1798 to be "ancient"). The SIZE of the earth was known (with reasonable accuracy) as long ago as around 250 B.C. By that time, it had pretty well been established that the earth was a sphere (on account of the shape of eclipse shadows and other evidence). Eratosthenes of Cyrene did a calculation involving the apparent angle of the sun as seen from two different cities a known distance apart from each other, and deduced the two cities were separated by 1/50 of a full circle. So he just multiplied their distance by 50 to get the circumference of the earth. The first measurement of the MASS of the earth had to wait another 2000 years. It was done in 1798, by measuring the strength of gravitational attraction between two known masses in a laboratory, and comparing that to the strength exerted on the masses by the earth (i.e., the masses' weight). Then you just multiply. > how do we know the distances to the other planets? Knowning that the planets travel in ellipses around the sun, You can use trigonometry to calculate the distances to planets RELATIVE TO the earth-sun distance. For example, by observing Venus you can see that it never gets farther than about 47° away from the sun in the sky. Then you can draw a right triangle with earth, the sun, and Venus at the three corners, and make one of the angles 47°, and with trigonometry you can see that Venus' orbit must be about 73% as big as the earth's. From that, you can then calculate the earth-Venus distance as a fraction of the earth-sun distance. But to turn that into a number of miles, you also have to know the earth-sun distance. The best early attempt at that was done by observing a transit of Venus (that is, the rare occasion when Venus crosses directly in front of the sun. During the transit, Venus can be seen (when safely filtered!) as a dark circle against the lighter disk of the sun.) When you observe the transit from two widely separated locations on earth, Venus's position against the sun's disk will appear very slightly displaced, due to parallax. (In the same way, if two different (separated) people are looking at a distant telephone pole against a background of mountains, the pole's position against the background will look slightly different from observer "A" to observer "B"). Anyway, by making very careful measurements of Venus' apparent position against the sun as seen from, say, Tahiti and Hudson Bay, you can use trigonometry to calculate the earth-sun distance as a multiple of the Tahiti-Hudson Bay distance. This was first done in the 1760's. > Please show you calculations. I've done enough to get you started. Search in Google if you want to know the details of the experiments.

Answer 4

the average mass density of the earth is=mass/volume
mass=5.98*10^24kg
volume=4/3(pi)r^3
4/3*22/7*38*10^4
1592381
density=0.00038*10^22

Answer 5

Volume of sphere which presumable is assumption you are making about earth's shape is 4/3 pir^3

Density =Mass / Unit Volume

So go calculate.

Kg/M^3 if you use answer below.

Answer 6

density = mass/volume

V = 4/3 * pi r^3

we calculate in MKSA r= 0.38*10^6 (you value is FALSE
r= 6.38*10^6m (Wilkipedia))

so V= 1.08810^21m^3

and specificmass is 5.9810^24/1.08810^21=5.510^3kg/m^3

or in more common units density = 5.5 g/cm^3