what mass of AgCl is produced to form 75.0g of AgNO3?
2007-05-13 23:44:06 · 2 answers · asked by sxe 1 in Science & Mathematics ➔ Chemistry
there is no mass of AgCl in AgNO3 because chlorine is not in that formula. if you want to find the mass of AgCl you will have to find the atomic mass of each and add them up together. fortunately for you i have both of those masses which are Ag= 107.87 and Cl= 35.45. the total mass is 143.32g.
2007-05-13 23:58:47 · answer #1 · answered by Milexis 1 · 0⤊ 0⤋
If you mean, "What mass of AgCl is produced from 75.0g AgNO3,"
Atomic weights: Ag=108 N=14 O=16 Cl=35.5 AgNO3=170 AgCl=143.5
75.0gAgNO3 x 1molAgNO3/170gAgNO3 x 1molAgCl/1molAgNO3 x 143.5gAgCl/1molAgCl = (75.0)(143.5)/(170) = 63.3gAgCl
The75.0g AgNO3 is given. The next factor comes from the formula weight of AgNO3. The g AgNO3 cancel, leaving moles AgNO3. The next factor comes from tghe balanced equation. The moles AgNO3 cancel, leaving moles AgCl. The final factor comes from the formula weight of AgCl. The moles AgCl cancel, leaving g AgCl.
2007-05-14 08:44:01 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋