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Could anyone help me to solve these four physics problems:


1) Boat's engine during 1 second can give speed v to L litres of water. What is the maximum speed of boat, if its mass is equal to M?


2) A comet flys to Earth with speed v. The angle between the speed vector and the straight, which connects Earth and the comet, is equal to alfa. What the value of speed v should be, that the comet:

a) would become a satellite of Earth;
b) would hit the Earth;
c) would escape from the gravitational influence of Earth;


3)A heavy metal ball starts to fall from 1 meter height, ant this ball hits a light tennis-ball on the table. After the hit, metall ball rises nearly to 1 meter height. To what height does a light tennis-ball rise?


4) A dumbbell (distance between balls is l) stands upright on a flat. This dumbbell is released to move. What speed will have each ball when the dumbbell hits the flat (there is no friction).

Thanks in advance.

2007-05-13 22:59:36 · 2 answers · asked by Pythagor 1 in Science & Mathematics Physics

Hi asddsadd

2007-05-14 03:48:51 · update #1

There are three parts in the second question. Each asks what speed does a comet should have that appropriate events would happen.

2007-05-14 04:01:20 · update #2

2 answers

1. m - L kg (1- liter of water = 1kg)

MV=mv

V= (m/M)v
V= (L/M)v

2. What was the question?

3. Not much as it transferred its energy to the metal ball

4. lower ball is stationary
the upper ball is a different story.

2007-05-14 03:13:00 · answer #1 · answered by Edward 7 · 0 0

whats up Tim, given mass m = 40 two kg additionally Mm / Me = a million/80 one.3 and Rm / Re = 0.27 Now stress in the international is offered via skill of the approach m*ge ge = 9.8 m/s^2 So stress on the mass on the earth = 411.6 N Now remember the expression g = GM/R^2 So gm / ge = Mm/Me * (Re/Rm)^2 consequently you will detect gm = ge * a million/80 one.3 * (a million/0.27)^2 Simplifying we get gm = a million.sixty 5 m/s^2 (just about) subsequently thecontinual on the equivalent mass via the moon is offered via skill of m*gm = 40 2*a million.sixty 5 = sixty 9.3 N As g cost on the moon is 9.8/a million.sixty 5 ie 5.ninety 4 events smaller than that on the earth, thecontinual on the mass too could be surprisingly much 6 events smaller.

2016-10-05 01:13:23 · answer #2 · answered by durrell 4 · 0 0

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