this is a maths question
2007-05-13 19:53:42 · 6 answers · asked by frank C 2 in Science & Mathematics ➔ Mathematics
28C6 = 28!/(6!*22!)
2007-05-13 19:58:33 · answer #1 · answered by P K 9 0 2 · 2⤊ 0⤋
The answer is "28-choose-6", or 28!/6!22! = 376,740.
This is because you can pick one of 28, then one of the remaining 27, then one of the remaning 26 and so on to get 28 * 27 * 26 * 25 * 24 * 23, or 28!/22!. However, we don't care about the order the girls are chosen in, so that a group of the same 6 girls is still considered the same group. So we have to divide by the number of ways to rearrange 6 people, of 6!.
2007-05-14 04:19:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
28!/22!=28*27*26*25*24*23=number of possibilities.
2007-05-14 03:05:09 · answer #3 · answered by electric 3 · 0⤊ 0⤋
i only want to add the comment that both 6 and 28 are perfect numbers.
2007-05-14 03:05:14 · answer #4 · answered by gjmb1960 7 · 1⤊ 0⤋
6*28 no?
if so, 168
2007-05-14 02:58:03 · answer #5 · answered by xmodry 2 · 0⤊ 2⤋
28C6 = 28!/(6!*22!)
2007-05-14 03:26:56 · answer #6 · answered by Fastian04 2 · 0⤊ 0⤋