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Heat engine operates between two reservoirs of 200K and 500k it absorbs 200cal what is max efficiency?

Also, what is max work?

2007-05-13 19:20:17 · 1 answers · asked by ron g 2 in Science & Mathematics ➔ Physics

1 answers

max efficiency = 100(500 - 200)/500 = 60%
max. work = 200*4.184 = 836.8 joules

2007-05-13 19:27:13 · answer #1 · answered by Helmut 7 · 0⤊ 1⤋

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