IF aluminum and copper wires of teh same length have the same resistance, which has the largest diameter? Why?

Question

I know the answer is aluminum but I don't understand why?

Answer 1

Two things you must know in order to answer this question:

#1 - the bigger the diameter of a wire, the less resistance there will be for electricity to flow through it.

#2 - Copper is a better conductor than Aluminum.

Since copper is a better conductor, the diameter must be smaller in order to create the same resistance as the aluminum wire.

For extra credit, tell your teacher that you want the thicker aluminum wire anyway because the cost of copper is so much higher than aluminum that even with the thicker wire, you'll save alot of money.

Answer 2

Yes, aluminum conductors are thicker then their copper counter point because it will heat up quicker than copper. Also, aluminum will react to the oxygen in the air when it carries a current, so this makes it a poor wire. Copper is less resistant then aluminum, and has more free electrons in it's outer shell to carry the current.

Answer 3

the respond remains the comparable as once you asked the question 9 hours in the past. The lengths would be proportional to the inverse of the resistivity. i.e the decrease the resistivity the longer the cord mandatory. L aluminium / L copper = r copper / r aluminium. it truly is often derived from R = L r / A ( the place r is the particular resistivity. R and A are consistent so L is proportional to a million/r I had assumed which you may placed the numbers right into a calculator to get the effect. L aluminium / L copper = r copper / r aluminium = a million.7/2.80 two = 0.60

Answer 4

The formula which gives the resistance of a wire is
R = ρL/A
where
ρ is the resistivity,
L is the length, and
A is the cross-sectional area.

Aluminum has a resistivity nearly twice that of copper, so an aluminum wire with the same resistance as a copper wire would have to have nearly twice the area..

Answer 5

Copper is better conductor, so thinner copper wire is equal to thicker aluminium wire.

R = P*l/A

since r1=r2 we have P1*L1/A1 = P2*L2/A2
since again, L1 = L2 we have

P1/P2 = A2/A1 This shows that the one with more specific resistance will require more area for the same resistance.

Aluminium wire will be thicker.