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integral x^3*e^(x^2) dx

im confused what do after i substitute u = x^2

I get (1/2)integral u*e^u du
do I do parts now?

thanks

2007-05-13 16:27:30 · 2 answers · asked by RelientKayers 4 in Science & Mathematics Mathematics

2 answers

Yep, from there it is a standard and fairly easy integration by parts.

(1/2) ∫ u.e^u du
= (1/2) (u e^u - ∫1.e^u du) where we differentiate u and integrate e^u du
= (1/2) (u e^u - e^u + c)
= (1/2) e^(x^2) (x^2 - 1) + c

2007-05-13 16:31:47 · answer #1 · answered by Scarlet Manuka 7 · 0 1

Let dv = e^(x^2) and u = x^3
Do parts three times, tabular integration will help here.
http://en.wikipedia.org/wiki/Integration_by_parts
http://www.maa.org/pubs/Calc_articles/ma035.pdf

2007-05-13 16:33:09 · answer #2 · answered by Joni DaNerd 6 · 0 0

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