Who can solve this mathematical quandry!?

Question

kara, Ty, Shalyn and neal decided to go bowling one night. they played girls vs. boys, with the combined scores determining the winners. Shalyn scored 18 less than kara. neal's score was 10 less than twice Shalyn's Neal outscored Ty by 21 points. If the total of all four scores was 529, what was the final score of the match?

Answer 1

s = k-18
n=2s-10
t=n+21
s+n+k+t=529

n=2(k-18) - 10
n=2k-36-10
n=2k-46

t=n+21
n=t-21
t-21=2k-46
t=2k-25

s+n+k+t=529
(k-18) + (2k-46) + k + (2k-25) = 529
6k - 89 = 529
6k = 618
k = 103

s = 103 - 18
s = 85

n = 2(85) - 10
n = 160

t = 160 + 21
t = 181

Answer 2

Let
k = Kara's score
s = Shalyn's score
t = Ty's score
n = Neal's score

Given:

s
k = s + 18
n = 2s - 10
t = n - 21 = (2s - 10) - 21 = 2s - 31

s + k + n + t = s + (s + 18) + (2s - 10) + (2s - 31)
529 = 6s - 23
6s = 552
s = 92

s = 92
k = s + 18 = 92 + 18 = 110
n = 2s - 10 = 2*92 - 10 = 174
t = 2s - 31 = 2*92 - 31 = 153

The teams are

s + k = 92 + 110 = 202
n + t = 174 + 153 = 327

Neal and Ty won by a score of 327 to 202.

Answer 3

K + T + S + N = 529
K + 18 = S
N = 2S - 10
N = T + 21

(S-18) + (N-21) + S + N = 529
2S + 2N - 39 = 529
2S + 2N = 568
(N + 10) + 2N = 568
3N = 558

N = 186
T = 165
S = 98
K = 80

N + T = 351
K + S = 178

NEAL AND TY WON