Surface area of a cylider?

Question

i need the know what the surface area of these 2 cylinders would be?
Cylinder #1 mearurements: r=5, h=14 (cm)

Cylinder #2 measurements: r=7, h=7.14 (cm)

What is the exact answer??

Answer 1

A = 2πr^2 + 2πrh = 2πr(r + h)
#1
A = 2π(5)(5 + 14)
A = 190π

#2
A = 2π(7)(7 + 7.14)
A = 197.96π

Answer 2

it depends on what surface area you want to find, circular, lateral or circular + lateral.

For Total surface area (circular + Lateral) :
Cylinder # 1 :

2(pi * r^2) + 2pi * r * h
= 2(3.142 * 5 ^2) + 2(3.142) * 5 * 14
= 596.91 cm^2

Cylinder # 2 : Try yourself !

Answer 3

Actually, the surg=face area is 2 x pi x r x h +2 pi x r^2
So for #1: 140 pi + 50 pi = 596.9 cm^2
For cylinder #2 : 99.96 pi + 98 pi = 621.9 cm^2

Answer 4

First Cylinder: 596.90 cm2
Second Cylinder: 621.90 cm2

Answer 5

use the formula S = pi * r^2 * h + 2*pi*r^2, where r is radius and h is cylinder height