a. Solve this equation for v in terms of w.
2v + 7 = w - 3
b. Solve this equation for s in terms of r.
4r + 5s + 2 = 8r - s + 7
c. Solve this equation for y in terms of x.
5y - 2x + 1 = 3(y + x) - (x - 5)
d. Solve the equation from question 2b for r in terms of s.
2007-05-13 15:56:15 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a. Solve this equation for v in terms of w.
2v + 7 = w - 3
2v=w-10
v= w/2 - 5
b. Solve this equation for s in terms of r.
4r + 5s + 2 = 8r - s + 7
6s=4r+5
s=(4r+5)/6
c. Solve this equation for y in terms of x.
5y - 2x + 1 = 3(y + x) - (x - 5)
5y-2x+1 = 3y+3x - x +5
2y=4x+4
2=2x+2
d. Solve the equation from question 2b for r in terms of s.
4r + 5s + 2 = 8r - s + 7
4r=6s-5
r=(6s-5)/4
hope it helps!
2007-05-13 16:01:33 · answer #1 · answered by xbonjoviaddictx 2 · 0⤊ 0⤋
a
2v = w - 10
v = (1/2).w - 5
b
6s = 4r + 5
s = (2/3).r + 5 / 6
c
5y - 2x + 1 = 3y + 3x - x + 5
2y = 4x + 4
y = 2x + 2
d
6s = 4r + 5
4r = 5 - 6s
r = 5 / 4 - (3/2).s
2007-05-14 11:53:21 · answer #2 · answered by Como 7 · 0⤊ 0⤋
2v = w-10
v = (w/2) -5
4r-8r = -s + 7 -2 -5s
-4r = -6s + 5
r = (3s/2) - (5/4)
5y -3y = 2x -1 +3x -x + 5
2y = 4x +4
y = 2x + 2
-4r = -6s + 5
s = (2r/3) + (5/6)
2007-05-13 23:05:26 · answer #3 · answered by looikk 4 · 0⤊ 0⤋